7x^(2/3)-20x^(1/3)-3=0

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Solution for 7x^(2/3)-20x^(1/3)-3=0 equation: 


x in (-oo:+oo)

7*x^(2/3)-(20*x^(1/3))-3 = 0

7*x^(2/3)-20*x^(1/3)-3 = 0

t_1 = x^(1/3)

7*t_1^2-20*t_1^1-3 = 0

7*t_1^2-20*t_1-3 = 0

DELTA = (-20)^2-(-3*4*7)

DELTA = 484

DELTA > 0

t_1 = (484^(1/2)+20)/(2*7) or t_1 = (20-484^(1/2))/(2*7)

t_1 = 3 or t_1 = -1/7

t_1 = -1/7

x^(1/3)+1/7 = 0

1*x^(1/3) = -1/7 // : 1

x^(1/3) = -1/7

( -1/7 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 3

x^(1/3)-3 = 0

1*x^(1/3) = 3 // : 1

x^(1/3) = 3

x^(1/3) = 3 // ^ 3

x = 27

x = 27

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